The SU(2) Chern–Simons field
The basic theoretical framework: why a $\mathrm{SU}(2)$ gauge field, what the Chern–Simons "action" is, and how the integer level $k$ fixes the fine-structure constant $\alpha_{EM} = 1/137$.
1. What is a "field"?
In physics, a field is a quantity defined at every point of spacetime. You already know:
- The temperature field $T(x,t)$: a value in degrees at each point
- The electric field $\vec{E}(x,t)$: a vector at each point
- The electromagnetic field $A_\mu(x,t)$: a 4-component vector at each point
In quantum particle physics, particles are quantum excitations of fields — the photon is an excitation of the electromagnetic field, the electron is an excitation of the Dirac field, and so on.
TQNT proposes a unified field, denoted $\chi$, which contains all of these excitations. And this field has a precise mathematical structure: it is an $\mathrm{SU}(2)$ gauge connection.
2. The SU(2) group: not so complicated
SU(2) is the set of complex $2 \times 2$ matrices $U$ that satisfy:
$$U^\dagger U = I_2 \quad \text{et} \quad \det(U) = 1$$Concretely, these are rotations in an abstract 3-dimensional space (the generators of SU(2) are the three Pauli matrices, divided by 2). Each element can be written as:
$$U(\vec{n}, \theta) = \cos(\theta/2)\, I - i\sin(\theta/2)\, \vec{n}\cdot\vec{\sigma}$$where $\vec{n}$ is a unit vector (the rotation "axis") and $\theta$ the angle. SU(2) is very close to the SO(3) group (ordinary 3D rotations), but is its double cover.
The choice of SU(2) is not arbitrary. It is the smallest non-abelian Lie group (where the order of operations matters), and therefore the simplest case in which non-commutativity appears — and it is this non-commutativity that makes Chern–Simons theory interesting. SU(3), SU(5), SO(10) are other possible choices, but they give different theories. TQNT is built on SU(2).
3. A connection: what is it?
A connection $A$ is essentially a gauge field — a mathematical object that says how to "parallel transport" a vector along a path in space, while respecting a given symmetry (here, the SU(2) symmetry).
Concretely, $A = A_\mu^a\, T^a\, dx^\mu$ where:
- $\mu \in \{0,1,2,3\}$ indexes spacetime coordinates
- $a \in \{1,2,3\}$ indexes the three generators $T^a$ of SU(2)
- $A_\mu^a(x)$ is a real number for each $\mu$ and $a$
In short, $A$ is a set of $4 \times 3 = 12$ functions $\mathbb{R}^{1,3} \to \mathbb{R}$.
4. The Chern–Simons action
In physics, the dynamics of a system are defined by its action $S$, and the physically realised configurations are those that minimise (or make stationary) $S$.
The Chern–Simons action, introduced by Shiing-Shen Chern and James Simons in 1974, is written:
$$S_{CS}[A] = \frac{k}{4\pi}\int_M \mathrm{tr}\!\left(A \wedge dA + \frac{2}{3}\, A \wedge A \wedge A\right)$$Do not be intimidated by the symbols: what matters is to understand its properties.
Three key properties
- Topological: $S_{CS}$ does not depend on the spacetime metric, only on the topology. This makes it a purely geometric object.
- The level $k$ is an integer: for the quantum theory to be consistent (in particular invariant under large gauge transformations), $k$ must be an integer $\in \mathbb{Z}$. This is a topological quantisation.
- Link with knots: Edward Witten showed in 1989 that the Chern–Simons partition functions computed on knots reproduce exactly the Jones polynomial of those knots. This fundamental link is what justifies the use of Chern–Simons in TQNT.
5. The level k = 135 and α = 1/137
In the quantum SU(2) Chern–Simons theory at level $k$, the unique deformation parameter is:
$$q = e^{2\pi i / (k+2)}$$If we identify $k+2$ with the inverse of the electromagnetic fine-structure constant:
$$\frac{1}{k+2} = \alpha_{EM} = \frac{1}{137{,}036\ldots}$$we obtain $k = 135.036 - 2 \approx 135$. Since $k$ must be an integer, we take $\boxed{k = 135}$, which gives $\alpha_{EM} \approx 1/137$. This is in very good agreement with the measured value (to within 0.03%).
Remarkable consequence: the fine-structure constant, which appears as a mysterious numerical value in the Standard Model, becomes in TQNT simply the inverse of the integer $(k+2)$. This is one of the most elegant results of the theory.
6. Flat connections and knots
The stable configurations of the field $\chi$ are the flat connections, that is, those that make the curvature vanish:
$$F_A = dA + A \wedge A = 0$$This means the field has no local "twist", but can carry a non-trivial global topological structure. On the complement of a knot $K$ (the space $\mathbb{R}^3 \setminus K$), flat connections form an algebraic space called the character variety.
It is this space that carries the information about particles: each point of the character variety corresponds to a possible configuration of the particle around its knot. Quantising this space gives the spectrum of physical states.
7. The Chern–Simons barrier: topological stability
Since the theory is topological, moving from one configuration to another that is topologically distinct (for instance, untying a knot) costs a finite action. In the instanton formulation, the transition rate is:
$$\Gamma_{\rm fuite} \propto e^{-S_{\rm inst}} \approx e^{-2k\pi}$$For $k = 135$, we get $e^{-2 \cdot 135 \cdot \pi} \approx e^{-848} \approx 10^{-368}$. This is astronomically small. The topological barrier makes simple knots (such as the electron or the proton) absolutely stable over any imaginable timescale.
TQNT relies on the SU(2) Chern–Simons theory at integer level $k = 135$. This theory is topological, its partition polynomial computes the Jones polynomial of knots, and $1/(k+2)$ is identified with the fine-structure constant. Particles are quantised excitations of the character variety of a knot complement, and the exponential topological barrier $e^{-2k\pi}$ explains the absolute stability of simple knots.
End-of-module quiz
Four questions to check your understanding of Chern–Simons and the level $k$.
1. Why must the level $k$ of Chern–Simons theory be an integer?
2. What value of $\alpha_{EM}$ does TQNT predict with $k = 135$?
3. What does "flat connection" mean in the TQNT context?
4. Why is the proton (almost) eternal according to TQNT?